Re: gcc invoked from make on cygwin strips symbols from object file

[Marco atzeri <marco dot atzeri at gmail dot com>]

On 9/19/2011 2:01 PM, Andrà Kwakernaak wrote:
> cccHi all,
>
> I'm porting an application from a Linux environment to Cygwin. During this process I encountered the following: it seems that invoking gcc from a Makefile behaves differently over gcc being invoked directly from the command line. When ggc is invoked from within a Makefile, symbols are stripped from the object file. When gcc is invoked with exactly the same arguments, the symbols remain in the object file.
>
> I've made a small test case, narrowing the problem down.
>
> Consider a C file containing the following:
> cyg
> #include<stdio.h>
>
> void hello()
>
> {
>
> 	printf("Hello world\n");
>
> }
>
> and a Makefile:
> hello.o:	
> 	gcc -c hello.c
>
> clean:
> 	rm -f *.o *.d *.exe
>
> When I run make an object file is build. The output of "nm hello.o" displays:
> 00000000 b .bss
> 00000000 d .data
> 00000000 t .text

this looks unlikely as hello.c miss the definition of printf

> If I run "gcc -c hello.c" directly from the command line I get object file for which nm displays:
> 00000000 b .bss
> 00000000 d .data
> 00000000 r .rdata
> 00000000 t .text
> 00000000 T _hello
>           U _printf
>
> As you can see in the latter case the expected symbols are in the object file.
> Why are they missing when using the Makefile? I can't get my head 
around it.
> I'm on Cygin 1.7.9, gcc 3.4.4, make 3.81
>
> Any help is greatly appreciated.
>
> Andrà Kwakernaak

is make the cygwin one ?

$ make --version
GNU Make 3.81
Copyright (C) 2006  Free Software Foundation, Inc.
This is free software; see the source for copying conditions.
There is NO warranty; not even for MERCHANTABILITY or FITNESS FOR A
PARTICULAR PURPOSE.

This program built for i686-pc-cygwin

$ which make
/usr/bin/make


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