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Re: [01/15] Introduce get_current_arch () function


>>>>> "Ulrich" == Ulrich Weigand <uweigand@de.ibm.com> writes:

Ulrich> There wouldn't really be much of a difference today, as the architecture
Ulrich> of val_args[i] is the architecture of the expression from which it was
Ulrich> evaluated, which is likewise get_current_arch ().

Is that true even if the expression is something like "$var"?
I did not read the patch series *that* closely, but I would have
assumed that the arch of the resulting value would come directly from
the convenience variable's value -- which could be anything.

Tom


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