[Bug c++/15111] New: GDB will not print the value of a variable ifthere exists a type of the same name

["mgretton at sourceware dot org" <sourceware-bugzilla at sourceware dot org>]

http://sourceware.org/bugzilla/show_bug.cgi?id=15111

             Bug #: 15111
           Summary: GDB will not print the value of a variable if there
                    exists a type of the same name
           Product: gdb
           Version: HEAD
            Status: NEW
          Severity: normal
          Priority: P2
         Component: c++
        AssignedTo: unassigned@sourceware.org
        ReportedBy: mgretton@sourceware.org
    Classification: Unclassified


Created attachment 6850
  --> http://sourceware.org/bugzilla/attachment.cgi?id=6850
Source for test case

Given the attached gdb-test.cpp file compiled as follows:
 $ g++ -O2 -g gdb-test.cpp -o gdb-test

This program has a structure named fibs and a global variable also named fibs. 
When you use gdb (as follows) you cannot get to the value of the global
variable because GDB seems to only see the typename:

 $ gdb ./gdb-test

 (gdb) start
 ...
 (gdb) print fibs
 Attempt to use a typename as an expression

(This is the instance of that error from gdb/expr.c)

The .debug_info section seems to be correct (objdump --dwarf=info output also
attached).

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