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Re: set $argv = *argv@100

From: Andrew Cagney <ac131313 at cygnus dot com>
To: Kevin Buettner <kevinb at redhat dot com>
Cc: gdb at sources dot redhat dot com
Date: Tue, 12 Feb 2002 10:32:10 -0500
Subject: Re: set $argv = *argv@100
References: <3C68AC89.4030807@cygnus.com> <1020212062154.ZM31975@localhost.localdomain>

> 
> I think the address is right.  The problem is that $argv isn't the right
> type.  According to the above, it's ``char **'' when it should be
> ``char *[100]''.
> 
> Try this:
> 
>     (top-gdb) set $argva = &(*argv@100)
>     (top-gdb) print $argva
>     $23 = (char *(*)[100]) 0xbffff99c
>     (top-gdb) ptype $argva
>     type = char *(*)[100]
>     (top-gdb) ptype *$argva
>     type = char *[100]
> 
> Kevin

Yes, C strikes again.  You can't copy an array, just its address :-(

sigh,
Andrew

References:
- set $argv = *argv@100
  - From: Andrew Cagney
- Re: set $argv = *argv@100
  - From: Kevin Buettner

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