Sorry, I'm again lost. I earlier wrote (note edits):
``No, ABI. For instance mipsIII and o32. The o32 ABI thinks
registers have 32 bits yet the real register has 64 bits. This gives
two [cooked] views of the same [raw] register. When o32 debug info
indicates a value in two adjacent [cooked] registers, it is refering
to 32 bit and not 64 bit registers.''
I'm not discussing which of these should be printed since that is
outside of the scope of this discussion.
(Sorry, the `what would this print' is a distraction.)
Suppose I have a program compiled to the o32 ABI which has a 64-bit
variable that the debug info says is in $a0. I'm running it on a MIPS
III machine. This means that half of my variable is in the low 32
bits of $a0, and the the other half is in the low 32 bits of $a1.
So, when you say that cooked registers are "ABI registers", are you
saying that, in the cooked register set, $a0 and $a1 would be 32-bit
registers, even though we're executing a 64-bit instruction set?
Having the register sizes disagree with the actual instructions being
executed is what seems like a bad idea to me.
As I pointed out in the above, there are two cooked $a0's. One is 32
bits and one is 64 bits. With regard to which should be user visible, I
wrote: