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Re: register != memory



Foremost among these is gdb's modeling of target
registers.  The model seems to presume vanilla
registers (e.g. gprs, fprs, pc, etc).

After writing to a register, everything is invalidated. Is this not happening?


Andrew


To provide the low level access needed by many
of our developers I have exposed many kernel-only
registers via g, G, and P.  Sadly the results
leave something to be desired because gdb seems
to believe that it can employ a memory-like model
for caching registers.

This breaks down when the user sets one of these
kernel-only registers.  I have numerous examples
where this results in a corrupted register cache:
  - readonly registers
  - bits that always read as zero or one
  - write-one to clear bits

Since the G message seems to be associated with
establishing thread state I simply ignore values
for any register that is not multiplexed by the
thread scheduler.


The P message is more of a problem.  Even when
returned an error (e.g. an attempt to modify a
readonly register) gdb reports the error to the
user but still updates its register cache.

A clean solution might be to allow an alternate
reply to a P message: Rval supplying the value
to be encached.

/john





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