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Single stepping a simple C-program, but...


Hi guys

I was a bit surprised today with GDB, and I hope one of you can explain it to me. Take a look at http://pastebin.org/37117
Press download and save as my_program.c
$ gcc -g my_program.c
$ gdb ./a.out
(gdb) br 7
Breakpoint 1 at 0x804838c: file my_program.c, line 7.
(gdb) r
Starting program: /home/pto/c/a.out


Breakpoint 1, main () at my_program.c:7
7	  if ((ii>3) || (ii<1))
(gdb) s
8	    printf("hej A\n");
(gdb) s
hej A
7	  if ((ii>3) || (ii<1))     <----------- WHY!!!!??
(gdb) s
12	  return 0;

-------

Why does the second "step" i.e. "s" take me BACK to line 7 after I have been in line 8????


Best


--
Peter Toft, Ph.D. [pto@linuxbog.dk] http://petertoft.dk


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