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[Bug regex/1201] regex.h problem when compiling with g++


------- Additional Comments From eggert at gnu dot org  2006-04-11 07:21 -------
I don't know which versions of g++ you're talking about, but the
abovementioned bug report from Bruno Haible says that no version of
g++ in the 3.2.*, 3.3.*, 3.4.*, 4.0.[01] series supports the
[__restrict] syntax, and I just now verified that g++ 4.1.0 does not
support it either; please see the shell transcript below.

Perhaps you confused __restrict with [__restrict]?  This change talks
about the latter, not the former.


586-penguin $ g++ -c t.cc
t.cc:21: error: expected primary-expression before '__restrict__'
t.cc:21: error: expected `]' before '__restrict__'
t.cc:21: error: expected ',' or '...' before '__restrict__'
587-penguin $ gcc -c t.cc
t.cc:21: error: expected primary-expression before '__restrict__'
t.cc:21: error: expected `]' before '__restrict__'
t.cc:21: error: expected ',' or '...' before '__restrict__'
588-penguin $ cp t.cc t.c; gcc -c t.c
589-penguin $ gcc --version | sed 1q
gcc (GCC) 4.1.0
590-penguin $ g++ --version | sed 1q
g++ (GCC) 4.1.0
591-penguin $ cat t.cc
#ifndef __restrict
# if ! (2 < __GNUC__ || (2 == __GNUC__ && 95 <= __GNUC_MINOR__))
#  if defined restrict || 199901L <= __STDC_VERSION__
#   define __restrict restrict
#  else
#   define __restrict
#  endif
# endif
#endif
/* gcc 3.1 and up support the [restrict] syntax.  */
#ifndef __restrict_arr
# if __GNUC__ > 3 || (__GNUC__ == 3 && __GNUC_MINOR__ >= 1)
#  define __restrict_arr __restrict
# else
#  define __restrict_arr
# endif
#endif

extern int regexec (const int *__restrict __preg,
		    const char *__restrict __string, int __nmatch,
		    int __pmatch[__restrict_arr],
		    int __eflags);


-- 
           What    |Removed                     |Added
----------------------------------------------------------------------------
             Status|WAITING                     |NEW


http://sourceware.org/bugzilla/show_bug.cgi?id=1201

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