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Re: strtof is not defined anymore in std=c++11
- From: Jon TURNEY <jon dot turney at dronecode dot org dot uk>
- To: newlib at sourceware dot org
- Cc: Corinna Vinschen <vinschen at redhat dot com>
- Date: Tue, 02 Apr 2013 20:10:17 +0100
- Subject: Re: strtof is not defined anymore in std=c++11
- References: <515AB4D3 dot 8060405 at st dot com> <20130402120003 dot GC32544 at calimero dot vinschen dot de>
On 02/04/2013 13:00, Corinna Vinschen wrote:
> On Apr 2 12:37, Laurent Alfonsi wrote:
>> The strtof function is now rejected when selecting the gcc C++11
>> standard option.
>> This regression has been introduced in this patch
>> http://sourceware.org/ml/newlib/2012/msg00425.html
>>
>> J.Turney patch is fine regarding the C standard side, but when using
>> from C++ :
>> $ cat a.cpp
>> #include <cstdlib>
>>
>> float f(const char *s, char **endptr) {
>> return strtof(s, endptr);
>> }
>>
>> It fails with the message :
>> $ g++ -std=c++11 a.cpp
>> a.cpp: In function 'float f(const char*, char**)':
>> a.cpp:3:30: error: 'strtof' was not declared in this scope
>>
>> Whereas this function strtof is well included in the cstdlib header
>> file defined in C++11 ISO.
>>
>> Please advice.
>
> Not sure. Enabling c++11 implies defining __STRICT_ANSI__ with gcc.
> Maybe we have to add something like this to the #if's guarding the
> declarations:
>
> || (defined (__cplusplus) && __cplusplus >= 201103L)
Yes. I think that all of the protoypes I touched: strtof(), strtoll(),
strtoull() and strtold() need this attention.
As currently written, it doesn't test if __STDC_VERSION__ is defined (and so
uses the assumed value of 0 when compiling C++), so do we actually need to
test if __cplusplus is defined?
Would you like me to write a patch?