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Re: $return in wildcarded void functions

Frank Ch. Eigler wrote:
On Wed, Mar 07, 2007 at 11:05:12AM -0600, David Smith wrote:
Hmm, I'm missing something. Why do we need $?var *and* $!var? It seems like $?var would suffice. 

The reason why it doesn't becomes clear with an example, and with the
realization that $var would still trigger a *translate-time* error if
it did not exist in context.

if ($?var) { use($!var) } // works even if $var would fail to translate

Ah, the idea makes sense now. But, how would the above translate? Would the entire statement get deleted (if $var didn't exist)?

--
David Smith
dsmith@redhat.com
Red Hat
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