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RE: setStylesheetParameter() question
- To: "'xsl-list at mulberrytech dot com'" <xsl-list at mulberrytech dot com>
- Subject: RE: setStylesheetParameter() question
- From: Brian Dupras <briand at centera dot com>
- Date: Wed, 23 Feb 2000 12:20:41 -0700
- Reply-To: xsl-list at mulberrytech dot com
Woops - you're right. I kinda misunderstood the structure of things - an
xsl:param is not a template parameter, it's a stylesheet paramater. :)
Thanks,
Brian
> -----Original Message-----
> From: Steve Tinney [mailto:stinney@sas.upenn.edu]
> Sent: Wednesday, February 23, 2000 10:46 AM
> To: xsl-list@mulberrytech.com
> Subject: Re: setStylesheetParameter() question
>
>
> > xsltProcessor.setStylesheetParam("testing", "'testing
> val'"); //note the
> > single quotes
> >
> > <xsl:template match="/">
> > <xsl:apply-templates>
> > <xsl:with-param name="testing"/>
> > </xsl:apply-templates>
> > </xsl:template>
> >
> > <xsl:template match="someelement">
> > <xsl:param name="testing"/>
> > <xsl:value-of select="$testing"/>
> > </xsl:template>
>
> Looks to me like it might help to:
>
> (a) declare a top-level xsl:param name="testing"
> (b) remove the declaration of the param in someelement
> (c) remove the xsl:with-param from the apply-templates
>
> Steve
>
>
> XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
>
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