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RE: XML -> XSL -> same XML
- To: "xsl-list at mulberrytech dot com" <xsl-list at mulberrytech dot com>
- Subject: RE: XML -> XSL -> same XML
- From: "Frederic FAURE" <frederic dot faure at gemplus dot com>
- Date: Thu, 09 Mar 2000 17:33 +0100
- Reply-To: xsl-list at mulberrytech dot com
This can be done with:
<xsl:template match="/ | * | @* | text()">
<whatever/>
<xsl:copy>
<xsl:apply-templates select="*|@*|text()"/>
</xsl:copy>
<whatever/>
</xsl:template>
-----Message d'origine-----
De: xsl-list@mulberrytech.com
Date: jeudi 9 mars 2000 18:00
À: xsl-list@mulberrytech.com
Objet: XML -> XSL -> same XML
How do I transform an XML with an XSL that spits out the same XML document
that was inputted, except with a particular heading or footer. Is there any way
I can do this without re-specifying every XML tag in the XSL?
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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