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RE: selecting a node without its children
- To: "'xsl-list at mulberrytech dot com'" <xsl-list at mulberrytech dot com>
- Subject: RE: selecting a node without its children
- From: "Selva, Francis" <Francis dot Selva at purchasepro dot com>
- Date: Thu, 30 Mar 2000 11:30:33 -0800
- Reply-To: xsl-list at mulberrytech dot com
Mike,
This is not working for me.Why?.I have to use
<xsl:template match="/">
<xsl:for-each select="STORY">
<xsl:for-each select="AUTHOR">
<xsl:value-of select="@id"/>
</xsl:for-each>
</xsl:for-each>
</xsl:template>
Where exactly the code u gave will work?.
Thanx,
Francis
> -----Original Message-----
> From: Kay Michael [mailto:Michael.Kay@icl.com]
> Sent: Thursday, March 30, 2000 7:07 PM
> To: 'xsl-list@mulberrytech.com'
> Subject: RE: selecting a node without its children
>
>
> > This is my XML
> >
> > <STORY>
> > <AUTHOR id="xsw">Stephen King</AUTHOR>
> > </STORY>
> >
> > If I have a template
> >
> > <xsl:template match="STORY">
> > ....
> > </xsl:template>
> >
> > how can i get the id attribute of author inside that template?
>
> <xsl:value-of select="AUTHOR/@id"/>
>
> Mike Kay
>
>
> XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
>
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