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Re: outputting the "position()" of parent

To: xsl-list at mulberrytech dot com
Subject: Re: outputting the "position()" of parent
From: David Carlisle <davidc at nag dot co dot uk>
Date: Wed, 7 Jun 2000 22:10:46 +0100 (BST)
References: <B1612D837360D111A9C000805FBBCCC901E87D07@geoffrey.sea.aspentech.com>
Reply-To: xsl-list at mulberrytech dot com



> How do I output the posistion of the parent. 
nodes don't have a position generally defined, they just have a position
in whatever node list was selected for the current processing.

so if for example you go apply-templates select=".." you will select
your parent but teh position will always be one as there is only one
node in the node list selected by  ..

probably you want to use xsl:number

David


 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list

References:
- outputting the "position()" of parent
  - From: Justin Friedl

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