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RE: counting and displaying with xsl?
- To: "'xsl-list at mulberrytech dot com'" <xsl-list at mulberrytech dot com>
- Subject: RE: counting and displaying with xsl?
- From: Kay Michael <Michael dot Kay at icl dot com>
- Date: Thu, 8 Jun 2000 11:14:02 +0100
- Reply-To: xsl-list at mulberrytech dot com
> Is there any way to use xsl to count the number of items in my
> xml? I'd like to know this so I could arrange them according to their
> number (e.g. have a line break every 5 items).
Outputting a line break is easy:
<xsl:if test="position() mod 5 = 1"><br/></xsl:if>
Other kinds of "grouping into sets of 5" are a bit more tricky, you need
something like
<xsl:template match="item[position() mod 5 = 1]">
<h2>Here are five items</h2>
<ul>
<xsl:apply-templates select="self::item | following-sibling::item[position()
< 5]"
mode="one-of-five"/>
</ul>
</xsl:template>
<xsl:template match="item" mode="one-of-five">
<li><xsl:value-of select="."/></li>
</xsl:template>
Mike Kay
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list