RE: Building menus

["Jarno Elovirta" <jarno at codeonline dot com>]

Hi

> I would like to build a menu that sorts the entrys by first character, and
> only display that character once even if several entrys begins with that
> character.
>
> Like this: [A]-[B]-[F]-[I]
>
> I have tryed to match the first character whith proceding-siblings first
> character, but i can't get it to work.

This uses keys for it, but it might be waste of time if you don't have that
many entries. You probably want HTML, hope this will help you with that.

[c:\temp]type menu.xml
<?xml version="1.0" encoding="ISO-8859-1"?>
<root>
  <entry name="Flls">
    <fo>lsfjlksdsdfjlsjfsf</fo>
  </entry>
  <entry name="Ajjf"/>
  <entry name="Bjjjdjj"/>
  <entry name="Ilsjdf"/>
  <entry name="Ajjjjj"/>
</root>

[c:\temp]type menu.xsl
<?xml version="1.0" encoding="ISO-8859-1"?>
<xsl:stylesheet version="1.0"
                xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

<xsl:output method="text" />

<xsl:key name="letter" match="/root/entry" use="substring(@name,1,1)"/>

<xsl:template match="root">
  <xsl:apply-templates select="entry[generate-id(.) =
generate-id(key('letter', substring(@name,1,1)))]">
    <xsl:sort select="@name" />
  </xsl:apply-templates>
</xsl:template>

<xsl:template match="entry">
  <xsl:text>[</xsl:text>
    <xsl:value-of select="substring(@name,1,1)" />
  <xsl:text>]</xsl:text>
  <xsl:if test="not(position() = last())">
    <xsl:text>-</xsl:text>
  </xsl:if>
</xsl:template>

</xsl:stylesheet>

[c:\temp]saxon menu.xml menu.xsl
[A]-[B]-[F]-[I]

--
Jarno Elovirta     jarno.elovirta@codeonline.com
CODEONLINE Ltd.    http://www.codeonline.com
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