This is the mail archive of the xsl-list@mulberrytech.com mailing list .


Index Nav: [Date Index] [Subject Index] [Author Index] [Thread Index]
Message Nav: [Date Prev] [Date Next] [Thread Prev] [Thread Next]

Re: Grouping by name(), and tagging first item of group



Par problem solved (below).  But I am still have problems:
I'm trying to call a template if the @TITLE is empty, to
produce some default text based on the name() of the element.
I'd be grateful for any suggestions: I've been thinking of

<xsl:apply-templates select="concat(name(),'_title')"/>

but it doesn't return a DOM node, so I'm wondering ....?

Thanks in anticipation,
lee



<xsl:if test="position()='1'">... seems to do it, 
at least where:

<xsl:template match="*">
	<xsl:apply-templates/>
</xsl:template>

<xsl:template match="/SPC">
	<xsl:apply-templates select="ITEM"/>
</xsl:template>

I wrote:

> <ROOT>
>   <ITEM>Foo</ITEM>
>   <ITEM title="This is a title">Bar</ITEM>
>   <DIFFERENTITEM>Baz</DIFFERENTITEM>
>   <DIFFERENTITEM title="This is a title">Pez</DIFFERENTITEM>
>   <ITEM>Tsk.</ITEM>
> </ROOT>
> 
> I wish to display a default title for the first occurance of
> each ROOT/* element, and then list all the elements with that
> name().


 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list

Index Nav: [Date Index] [Subject Index] [Author Index] [Thread Index]
Message Nav: [Date Prev] [Date Next] [Thread Prev] [Thread Next]