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Re: question with using Muenchian/xsl:key (Re: sort/group/count p roblem)


Xiaocun Xu wrote:
> Since my goal is to find the sum of @units for all items with the same
> @itemid under the same itemlist parent, I tried:
> sum(item[count(.|key('items-by-itemid',@itemid)[count(.|$this_lists_
> items)=count($this_lists_items)][1])=1]/@units)
> which returned me "0".
> 
> Is this the right way to find the sum of the node-set intersect?

I'm not convinced you are selecting the right items. At the point where
you use refer to @itemid in your key(), the context has changed (you are
inside a predicate) .. try replacing @itemid there with a variable that
you set outside, as you did with $this_lists_items.

Understand that until Jeni Tennison sees this thread, you can't expect a
detailed, thoroughly tested reply with all the code you need to solve your
problem :)

   - Mike
____________________________________________________________________
Mike J. Brown, software engineer at         My XML/XSL resources:
webb.net in Denver, Colorado, USA           http://www.skew.org/xml/


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