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RE: Converting attributes into child elements
- To: xsl-list at mulberrytech dot com
- Subject: RE: Converting attributes into child elements
- From: jlangdon at monmouth dot com
- Date: Mon, 13 Nov 2000 10:38:49 EDT
- Reply-To: xsl-list at mulberrytech dot com
> > The test transformation works well, I just need to manage/format the
> > white space to make the data more legible.
>
> Does <xsl:output indent="yes"> do the job?
>
> Mike Kay
Yes. I also used <xsl:strip-space elements="*"/> as you can see by the
code. I would like to take the attributes that were transformed into
child elements and lay them out in a column format. Suggestions? Do I
combine the xsl file with some html/css to achieve this?
Thanks again Mike.
Regards,
Jeff Langdon
<!-- xml file -->
<?xml version="1.0" encoding="utf-8" ?>
<?xml-stylesheet type="text/xsl" href="attributes.xsl"?>
<contactInfo>
<person fname="John" lname="Doe" address="123 Main Street"
city="Princeton" zipcode="08800"></person>
<person fname="John" lname="Doo" address="456 Main Street"
city="Trenton" zipcode="08801"></person>
<person fname="John" lname="Doh" address="789 Main Street"
city="Jamesburg" zipcode="08802"></person>
/contactInfo>
<!-- xsl file -->
<xsl:stylesheet
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
version="1.0">
<xsl:strip-space elements="*"/>
<xsl:output indent="yes"/>
<xsl:template match="person">
<xsl:copy>
<xsl:for-each select="@*">
<xsl:element name="{name()}"><xsl:value-of select="."/></xsl:element>
</xsl:for-each>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
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