Re: How to test if the current node is an attribute or a namespace node?

[Miloslav Nic <nicmila at idoox dot com>]

I agree.

I would use the count()  one for on-line processing, but
when I am not worried about performance I am always trying
to find an expression which evokes in my head immediately, what
I want to achieve. 

count() algorithm is clever, but it takes some time (at least for me) 
to realize, what is going on.


Dimitre Novatchev wrote:
> 
> Miloslav Nic wrote:
> 
> > Kay Michael wrote:
> > >
> > > > Which is the simplest XPath expression to test whether the
> > > > current node is an attribute?
> > >
> > > Not easy! I'd suggest:
> > >
> > > count(. | ../@*) = count(../@*)
> > > >
> > > > Or a namespace?
> > > >
> > > count(. | ../namespace::*) = count(../namespace::*)
> > >
> > > Mike Kay
> >
> >
> > Longer, but probably easier to understand:
> >
> > generate-id() = generate-id(parent::*/@*[name()=name(current())])
> 
> Also probably considerably less efficient.
> 
> Dimitre Novatchev.
> 
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