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How to select distinct combined element values
- To: xsl-list at lists dot mulberrytech dot com
- Subject: [xsl] How to select distinct combined element values
- From: "Albert Tsun" <albert dot tsun at excel dot com dot hk>
- Date: Thu, 21 Dec 2000 12:06:15 +0800
- Reply-To: xsl-list at lists dot mulberrytech dot com
Dear All,
I got a problem in getting distinct element group values.
XML source:
+++++++++++
<match>
<date>1-11-2000</date>
<team>Brazil</team>
<group>A</group>
<score>1</score>
</match>
<match>
<date>2-11-2000</date>
<team>Brazil</team>
<group>A</group>
<score>1</score>
</match>
<match>
<date>1-11-2000</date>
<team>Brazil</team>
<group>B</group>
<score>1</score>
</match>
<match>
<date>1-11-2000</date>
<team>Argentina</team>
<group>A</group>
<score>1</score>
</match>
<match>
<date>1-11-2000</date>
<team>Argentina</team>
<group>A</group>
<score>1</score>
</match>
for distinct team :
In XSL, I can use
<xsl:variable name="teams" select = "//team[not(.=preceding::team)]"/>
to get
Brazil
Argentina
However, if I want to get distinct team, group, that is
Brazil A
Brazil B
Argentina A
How can I do it ? would Mike give me some suggestion ?
TIA
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