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RE: performance of copying all source to result
- To: "'xsl-list at lists dot mulberrytech dot com'" <xsl-list at lists dot mulberrytech dot com>
- Subject: RE: [xsl] performance of copying all source to result
- From: Evyatar_Kafkafi <evyatar at orsus dot com>
- Date: Thu, 21 Dec 2000 12:28:46 +0200
- Reply-To: xsl-list at lists dot mulberrytech dot com
Actually, I started with match="*", and only later tried the "a | applet |
..." approach.
Unfortunately, both methods are slow and no method is quicker than the
other.
As to the copy-of advice, I'll try that.
Evyatar
-----Original Message-----
From: David Carlisle [mailto:davidc@nag.co.uk]
Sent: Thursday, December 21, 2000 11:55 AM
To: xsl-list@lists.mulberrytech.com
Subject: Re: [xsl] performance of copying all source to result
wouldn't match="*" be quicker than
<xsl:template match=" a | applet | b | big | body | br | caption |
cite | code | col | colgroup | dd | div | dl | dt | em | font |
form | frame | frameset | head | h1 | h2 | h3 | h4 | h5 | h6 | hr |
html | i | iframe | img | link | li | map | meta | noframes | ol |
p | param | pre | s | script | small | span | strong | style |
sub | sup | td | th | title | tr | tt | ul | var | table ">
you can still overide that with more specific templates for elements you
don't want to copy.
Also, if there are any elements for which you want always want to copy
the whole branch, you may find it quicker to use copy-of select="."
rather than <xsl:copy and xsl:apply-templates.
David
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