This is the mail archive of the
xsl-list@mulberrytech.com
mailing list .
Re: Namespace questions
- To: akotzer at savvion dot com
- Subject: [xsl] Re: Namespace questions
- From: Dimitre Novatchev <dnovatchev at yahoo dot com>
- Date: Fri, 29 Dec 2000 23:22:55 -0800 (PST)
- Cc: xsl-list at lists dot mulberrytech dot com
- Reply-To: xsl-list at lists dot mulberrytech dot com
Ayelet,
You can get rid of the namespace declaration on the child nodes by
adding the following to your xsl:stylesheet element:
xmlns:m="B" exclude-result-prefixes="m"
Then you'll get in your output:
<A1>something </A1><A2 att="att1">something </A2>
However, the top element(s) that declare the namespace will still be
copied with the namespace declaration. So, the result of processing
your fragment will look like this:
<m:A xmlns:m="B"><A1>something </A1><A2 att="att1">something
</A2></m:A>
Obviously, you must have a separate template that matches all
m:yourNames elements you'd like to copy without the namespace
declaration on them. Then in this template use xsl:element and
xsl:attribute and specify the local-name().
Dimitre.
Ayelet Kotzer wrote:
(Desired) Output:
<A >
<A1>something </A1>
<A2 att="att1>something </A2>
</A>
What I got is something like this:
<A1 xmlns:m="B">something </A1>
<A2 xmlns:m="B" att="att1 >something </A2>
__________________________________________________
Do You Yahoo!?
Yahoo! Photos - Share your holiday photos online!
http://photos.yahoo.com/
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list