[xsl] xsl:when - comparing parameter and element values

["RUSSO, EDITH" <EDIRUS at SAFECO dot com>]

I can't get the right syntax for the comparison between the two values for
xsl:when.
What I want to test is when the 'showcasemgmt' parameter contains the value
"true" and the element 'casemgmtind' contains the value "FALSE".
The second part to my question is...only if this case is NOT satisfied, do I
want to output a <tr>, if I leave the contents of the "when" empty, will
that work?

Thanks - Edith

Here's my xml and xsl:

<?xml version="1.0"?>
<PATHFINDER version="2000">
<Task>
<DueDate>10/4/00</DueDate>
<StartDate>10/2/00</StartDate>
<Subject>Arbitration Brief - Prepare</Subject>
<AssignTo>xxx</AssignTo>
<DateCompleted>10/24/00</DateCompleted>
<IsRecurring>FALSE</IsRecurring>
<CaseMgmtInd>FALSE</CaseMgmtInd>
<EntryID>111</EntryID>
</Task>
</PATHFINDER>

<?xml version="1.0" ?> 
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
version="1.0"> 
...
	<xsl:param name="showcasemgmt">true</xsl:param>
	<xsl:template match="/">
...
				<xsl:apply-templates
select="PATHFINDER/Task">
...
	<xsl:template match="PATHFINDER/Task">
		<xsl:choose>
			<xsl:when test="$showcasemgmt='true' &&
CaseMgmtInd='FALSE'"></xsl:when>
			<xsl:otherwise>
				<tr>
...
			</xsl:otherwise>
		</xsl:choose>			
	</xsl:template>
</xsl:stylesheet>


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