Re: [xsl] Newbie document() question

["G. Ken Holman" <gkholman at CraneSoftwrights dot com>]

At 01/01/12 08:29 -0800, Edmund Mitchell wrote:
>I've tried
>
><xsl:variable name='otherDoc' select='document(MyXml.xml)'/>
><xsl:template match='/'>
><xsl:copy-of select='$otherDoc'/>...
>
>as well as just
>
><xsl:template match='/'>
><xsl:copy-of select='document(MyXml.xml)'/>...
>
>but neither produced output, so I can't even seem to get off the ground with
>this, let alone do any combining.

Don't kick yourself for this, Edmund, but you are asking for the document 
named by the value of the child element named MyXml.xml.

Try:  select='document("MyXml.xml")'

This will supply the string of your filename to the function.

Note that you are working with a relative URI value here, so the presence 
and value of a second argument is going to be significant to where you want 
to find the file.  Check Module 8 of your class notes (readers of our book 
will also find the details in chapter 8).

I hope this helps.

...................... Ken

--
G. Ken Holman                      mailto:gkholman@CraneSoftwrights.com
Crane Softwrights Ltd.               http://www.CraneSoftwrights.com/s/
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