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Re: problem with Passing Parameters to Templates
- To: xsl-list at lists dot mulberrytech dot com
- Subject: Re: [xsl] problem with Passing Parameters to Templates
- From: "helen li" <helen_p_li at hotmail dot com>
- Date: Mon, 22 Jan 2001 10:09:48 -0500
- Reply-To: xsl-list at lists dot mulberrytech dot com
Also I have tried to use the following code to find and give the value of
the element that is a descendant of the current node that is called 'codec'.
It does not work either.
<xsl:template name="opt_template">
<xsl:param name="node"></xsl:param>
<xsl:variable name="node-element"
select=".//*[local-name() = $node]" />
<xsl:if test="$node-element">
<xsl:value-of select="$node-element" />
</xsl:if>
</xsl:template>
Thanks,
Helen
>From: "helen li" <helen_p_li@hotmail.com>
>Reply-To: xsl-list@lists.mulberrytech.com
>To: xsl-list@lists.mulberrytech.com
>Subject: Re: [xsl] problem with Passing Parameters to Templates
>Date: Mon, 22 Jan 2001 09:43:41 -0500
>
>Hi Jeni&David,
>
>Thanks for your help.
>
>What I really want to do is to output the value of element codec(not the
>value of variable $node) if the element codec exists. With the following
>code, I did not get the result as expected. Did I do something wrong?
>
> <xsl:template name="opt_template">
> <xsl:param name="node"></xsl:param>
> <xsl:if test=".//*[$node]">
> <xsl:value-of select=".//*[name()=$node]"/>
> </xsl:if>
> </xsl:template>
>
> <xsl:call-template name="opt_template">
> <xsl:with-param name="node" select="'codec'"/>
> </xsl:call-template>
>
>Thanks again,
>
>Helen
>
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