Re: [xsl] xsl to echo input xml

[Mike Brown <mike at skew dot org>]

_ryan wrote:
> If I want to pass an xml to an xsl, and then have the xsl simply repeat
> what's in the xml, how would I go about that? 

What you want is called an "identity transformation" and it is explained
in the XSLT spec in section 7.5, at http://www.w3.org/TR/xslt#copying

The template is 

<xsl:template match="@*|node()">
  <xsl:copy>
    <xsl:apply-templates select="@*|node()"/>
  </xsl:copy>
</xsl:template>

The reason why your template won't work should be self-evident after
reading sections 5.1, 5.4, and 5.8:

http://www.w3.org/TR/xslt#section-Processing-Model
http://www.w3.org/TR/xslt#section-Applying-Template-Rules
http://www.w3.org/TR/xslt#built-in-rule

Note that XSLT only has access to the logical contents of the XML document
as reported by a parser, so 'physical' structures like entity references
and attribute order may not be preserved in your output.

   - Mike
____________________________________________________________________
Mike J. Brown, software engineer at            My XML/XSL resources: 
webb.net in Denver, Colorado, USA              http://skew.org/xml/

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