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about xsl:when
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- Subject: [xsl] about xsl:when
- From: dago at energystudios dot com
- Date: Thu, 8 Mar 2001 11:19:04 -0500
- Reply-To: xsl-list at lists dot mulberrytech dot com
Hi all,
I try that display the names that have the 'id=1' and 'id=2' in the resutl,
but doesen't work. In the XML file, each 'persona' node have a 'id' with
numeric value. This is the xsl code:
<xsl:template match = "persona[@id]" >
<xsl:choose >
<xsl:when test = ".='1'" > <br/>
edad=<xsl:value-of select="name"/>
</xsl:when>
<xsl:when test = ".='2'" > <br/>
edad=<xsl:value-of select="name"/>
</xsl:when>
<xsl:otherwise > <br/>
<xsl:text >no hay</xsl:text>
</xsl:otherwise>
</xsl:choose>
</xsl:template>
Thnanks for you help,
Dago Flores.
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