Re: [xsl] Copy XHTML element contents without base tag

[cutlass <cutlass at secure0 dot com>]

look at faq on copying
http://www.dpawson.co.uk/xsl/N1930.html
Nick Vincent wrote:

> Hi all,
> 
> This is probably painfully easy, but I can't think of a solution:
> 
> I need to include a raw XHTML fragment in my XSL:
> 
> <document>
> 	<xfragment>
> 		This is a fragment of XHTML
> 		<table><tr><td>
> 			[snip dull HTML]
> 		</td></tr></table>
> 	</xfragment>
> </document>
> 
> Now, as far as I can see there are two ways of processing this in XSLT:
> 
> <xsl:template match="xfragment">
> 	<xsl:copy-of select="." />
> </xsl:template>
> 
> Unfortunately this ends up including the <xfragment> tags in the output,
> which I can't really have.
> 
> The other way I can see is 
> 
> <xsl:template match="xfragment">
> 	<xsl:copy-of select="./*" />
> </xsl:template>
> 
> Unfortunately this removes any text elements which are direct children of
> the xfragment tags (e.g. the phrase 'This is a fragment of XHTML' in the
> above example).
> 
> Does anyone know any better ways of making this copy?
> 
> Thanks,
> 
> 
> Nick Vincent
> NeoWorks
> 
> 
>  XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
> 
> 
> 


 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list