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RE: How to specify a path to a node in a nodeset using a variable
- To: <xsl-list at lists dot mulberrytech dot com>
- Subject: RE: [xsl] How to specify a path to a node in a nodeset using a variable
- From: "Shakeel Mahate" <shakeelmahate at hotmail dot com>
- Date: Tue, 13 Mar 2001 18:20:16 -0700
- Cc: <shakeelmahate at hotmail dot com>
- Reply-To: xsl-list at lists dot mulberrytech dot com
From: "Michael Kay" <mhkay@iclway.co.uk>
>The suggestion was not to concatenate $container and $path, it was to
>concatenate '$container/' and $path, that is to construct a string
>consisting of the string '$container/' followed by (the value of $path
>converted to a string); the resulting string will contain an XPath
>expression which the evaluate() function then evaluates.
I tried it and it works!!! But it is a mystery what exactly is
saxon:evaluate() doing?
It receives the following argument $container//account/person/@name because
of the concat function.
concat('$container/', $path) where $path is /account/person/@name
Is $container//account/person/@name a valid XPath expression?
I tried looking up the documentation for the saxon:evaluate and
xalan:evaluate() but I couldnt answer the question.
Do I need an extra slash between $container and the $path?
-Shakeel
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