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Re: Comment about XSLT Complier?
- To: <xsl-list at lists dot mulberrytech dot com>, <xsl-FO at egroups dot com>
- Subject: Re: [xsl] Comment about XSLT Complier?
- From: "Carmelo Montanez" <carmelo at nist dot gov>
- Date: Thu, 15 Mar 2001 04:18:12 -0500
- References: <000e01c0ad6c$acb52600$3b3a3c3e@oemcomputer>
- Reply-To: xsl-list at lists dot mulberrytech dot com
Hi all:
Does anyone knows how to get the aboslute value of an element
within a tree? and by that I mean the order on which it is listed
within that tree. Look at the tree below
<child1>
</child1>
<child2>
<child2-1>
<child2-1-1>
<child2-1-1-1>
</child2-1-1-1>
</child2-1-1>
</child2-1>
</child2>
<child3>
<child3-1>
</child3-1>
</child3>
<child4>
</child4>
</parent>
To be more clear I am looking for this type of information
"child1" - is number 1
"child2" - is number 2
"child2-1" - is number 3
"child2-1-1" is number 4
"child2-1-1-1" is number 5
"child3" is number 6
"child3-1" is number 7
"child4" is number 8
and so on ....
in other words its "absolute position" as you read from to to bottom and
I want to know that information when THAT node is the context node
in other words if "child6" is the current node I want to know that
it is really number 6 as I read. Any ideas?
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