Re: [xsl] Transform min and max values to list?

[Ronald <ronald at salience dot nl>]

Maybe you could try 2 construct a loop:

<xsl:call-template name="for.loop">
         <xsl:with-param name="i">1</xsl:with-param>
         <xsl:with-param name="count">10</xsl:with-param>
</xsl:call-template>


<xsl:template name="for.loop">
         <xsl:param name="i"/>
         <xsl:param name="count"/>
         <xsl:if test="$i &lt;= $count">
<!--    body of the loop goes here    -->
         </xsl:if>
         <xsl:if test="$i &lt;= $count">
                 <xsl:call-template name="for.loop">

                         <xsl:with-param name="i">
                                 <!-- Increment index-->
                                 <xsl:value-of select="$i + 1"/>
                         </xsl:with-param>
                         <xsl:with-param name="count">
                                 <xsl:value-of select="$count"/>
                         </xsl:with-param>
                 </xsl:call-template>
         </xsl:if>
</xsl:template>
(code-bit in XML cooktop!)


ronald

At 05:41 PM 4/19/01 +1000, you wrote:
>I want to transform this element:
>
><number min="1" max="3"/>
>
>into this:
>
><select>
>   <option>1</option>
>   <option>2</option>
>   <option>3</option>
></select>
>
>I have looked at for-each but its select attribute requires a node-set. Is
>there a simple way to achieve what I want?
>
>Thanks in advance.
>
>--
>Michael Strasser
>Brisbane, Australia
>
>  XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list


 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list