Re: [xsl] copy-of question

["Franz Figl" <frafi at augusta dot de>]

Jeni, thanks again for the good explanation. Now I am beginning to
understand...
Franz




> Hi Franz,
>
> > Jeni, I don't have a deep copy here (I want the complete original
> > html table inside the xml), but only the table text cells as output
>
> Sorry - I don't understand what you mean by the above. Let me try
> again. You said:
>
> > how can I extract only one element in original form?
> > copy-of seems to work here, but I have all the other unwanted tags also
as
> > plain text.
> > Is this related to the default rules?
> >
> >  <xsl:template match="TABLE">
> >    <xsl:copy-of select="."/>
> >  </xsl:template>
>
> If this is the only template you have in your stylesheet, it will give
> you a (deep) copy of any TABLE elements in your document.  The rest of
> the nodes in the stylesheet (aside from those under the TABLE
> elements) will have the built-in templates applied to them.  The
> effect of these built-in templates is that you get the text of the
> rest of the document output.
>
> If you don't want that text to be output, then adding the empty
> template:
>
> <xsl:template match="text()" />
>
> will stop it being output.  You'll still get the (deep) copy of the
> TABLE elements, but this seemed to be what you were after (you said
> that was working).
>
> If you have a stylesheet with these two templates in it, and you're
> only getting the text of the table cells in your output, then I bet
> you've got an xsl:output instruction that looks like:
>
> <xsl:output method="text" />
>
> Take out that xsl:output instruction, or replace it with one that
> looks like:
>
> <xsl:output method="xml" />
>
> If you use the 'text' method, the XSLT processor doesn't output any
> elements that you create, only text nodes.
>
> I hope that helps,
>
> Jeni
>
> ---
> Jeni Tennison
> http://www.jenitennison.com/
>
>
>
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>
>


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