Re: [xsl] How to test if a node is a descendant of a specific ancestor

[Ronald <ronald at salience dot nl>]

It seems to me some reading on xsl and xpath would do much for you.

If you haven't got the time to do so, here's the code :-)

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
           version="1.0">

<xsl:template match="/">
  <xsl:apply-templates/>
</xsl:template>

<xsl:template match="//string">
   <xsl:if test="ancestor::head-row">
       <p class="head-row">some content1</p>
   </xsl:if>

   <xsl:if test="ancestor::body-row">
       <p class="body-row">some content2</p>
   </xsl:if>
</xsl:template>

</xsl:stylesheet>


Ronald

At 02:47 PM 4/26/01 +0200, you wrote:
>Hello!
>
>I have an xml file that looks like the following:
>
><layout>
>     <head-row>
>         <data>
>             <string>
>             </string>
>         </data>
>     </head-row>
>
>     <body-row>
>         <data>
>             <string>
>             </string>
>         </data>
>     </body-row>
></layout>
>
>Then I have a template rule in an XSL file that looks like the following:
>
><xsl:template match="//string">
>.......Pseudo code:
><test if the current context node is a descendant of head-row>
>     <p class="head-row">some content</p>
></test>
>
><test if the current context node is a descendant of body-row>
>     <p class="body-row">some content</p>
></test>
>...........
>
>
>How can I test this?
>
>
>Sebastian Schirmer
>
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