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Re: Accessing nth element
- To: xsl-list at lists dot mulberrytech dot com
- Subject: Re: [xsl] Accessing nth element
- From: Bharat dot Chintapally at CommerceQuest dot com
- Date: Tue, 1 May 2001 09:30:42 -0400
- Reply-To: xsl-list at lists dot mulberrytech dot com
I am sorry correction: I am not using for-each but I am using templates.
Should I switch to for-each with a selection to achieve what I am doing..
Thanks
--bharat
---------------------------------------------------------------
Bharat Chintapally
CommerceQuest Inc.
bharat.chintapally@commercequest.com
New Phone # 813-639-6478
---------------------------------------------------------------
Janning Vygen
<vygen@planwerk6.de> To: xsl-list@lists.mulberrytech.com,
Sent by: Bharat.Chintapally@CommerceQuest.com
owner-xsl-list@lists.mulber cc:
rytech.com Subject: Re: [xsl] Accessing nth element
05/01/01 09:23 AM
Please respond to xsl-list
Am Dienstag, 1. Mai 2001 15:04 schrieb
Bharat.Chintapally@CommerceQuest.com:
> Hello all:
> I think I need to replace for-each in my XSLT's with recursion. I am
> interested in picking 'x' elements from 'y' (20 for each page from 500
> records) for paging. for-each is working fine, but it is overkill, I
should
> be able to terminate (return from as in procedural lang's) processing
when
> I finish processing 20 records for a given page.
> I am trying to switch to recursion, but have a quick question. Is
> there a way to fetch an n'th element from given bunch of records. For
> example when I am processing records 20 thru records 40 out of 500
records,
> I would like directly fetch the record #20 from all the records. Is it
> possible..
try something like this
<xsl:for-each select="./records[position() < 20]">
not tested, but with position function inside your XPath expression you
should get the records you want.
janning
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