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Re: XSL to generate XPaths


> Here I needed to check if the current node is an element:
> 
>   count(.|../*)=count(../*) and count(../*[name()=name(current())]) > 1"

Perhaps self::* in the first place is more efficient?
(self::* selects element nodes only)

Cheers,
Oliver


/-------------------------------------------------------------------\
|  ob|do        Dipl.Inf. Oliver Becker                             |
|  --+--        E-Mail: obecker@informatik.hu-berlin.de             |
|  op|qo        WWW:    http://www.informatik.hu-berlin.de/~obecker |
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