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Re: XSL to Sort XML Doc return XML


Hi Xiaocun and xsl-list,

I am a novice and thought I would try your solution for myself.  I had to
wrap up your xsl a little bit and have produced the following two flavours
of code that work (one with for-each, the other with apply-templates).

for-each flavour:
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>

<xsl:output method="xml"/>

<xsl:template match="/">

<records>
	<xsl:for-each select="records/record">
		<xsl:sort select="."/>
		<record><xsl:value-of select="."/></record>
	</xsl:for-each>
</records>

</xsl:template>

</xsl:stylesheet>

apply-templates flavour:
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>

<xsl:output method="xml"/>

<xsl:template match="/">
	<xsl:apply-templates/>
</xsl:template>

<xsl:template match="records">
	<records><xsl:apply-templates><xsl:sort
select="."/></xsl:apply-templates></records>
</xsl:template>

<xsl:template match="record">
	<record><xsl:value-of select="."/></record>
</xsl:template>

</xsl:stylesheet>

I am at a bit of loss as to which approach would be better (and I don't even
know how to name these two approaches).  Can you recommend a reference/web
tutorial/whatever that will help me better understand the design patterns
being used and when to use which?

Thanks,

J.


> From: Xiaocun Xu [mailto:xiaocunxu@yahoo.com] 
> Sent: Thursday, May 31, 2001 2:49 PM
> To: xsl-list@lists.mulberrytech.com
> Subject: Re: [xsl] XSL to Sort XML Doc return XML
> Doc ?
> 
> Hi, Matt:
> 
>   This can be done pretty easily with xsl:sort,
> like:
> <records>
> <xsl:for-each select="records/record">
> 	<xsl:sort select="."/>
> 	<record><xsl:value-of select="."/></record>
> </xsl:for-each>
> </records>


James MacEwan
Software Developer
Investors Group Inc.
mailto:James.MacEwan@investorsgroup.com
v: (204) 956-8515
f: (204) 943-3540


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