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RE: Sorting date in xsl
- To: <xsl-list at lists dot mulberrytech dot com>
- Subject: RE: [xsl] Sorting date in xsl
- From: "Hahn, Kimberly" <Kim dot Hahn at enform dot com>
- Date: Mon, 11 Jun 2001 14:13:44 -0500
- Reply-To: xsl-list at lists dot mulberrytech dot com
If you convert the date into a string of numbers:
Tue, 29 May 2001 22:37:32
to
20010529223732
That creates a sortable value that should work. Just make sure that you
always have 4 digits for the year and 2 for the month, day, hours, minutes
and seconds - basically always the same number of characters for each time
representation. Otherwise you will not get a proper sort, ie. dec 29 1980
would be a larger number then may 29 2001 (19,801,229 to 2,001,529 vs.
19,801,229 to 20,010,529).
-----Original Message-----
From: owner-xsl-list@lists.mulberrytech.com
[mailto:owner-xsl-list@lists.mulberrytech.com]On Behalf Of Gitanjali
Sent: Saturday, June 09, 2001 6:39 AM
To: xsl-list@lists.mulberrytech.com
Subject: [xsl] Sorting date in xsl
Can any body tell me how to sort in xsl. Do I need to conver the following
format to number and then do sorting..
Thanks
Narsu
<root>
<date>Tue, 29 May 2001 22:37:32 -0400</date>
<date>Tue, 25 May 2001 22:37:32 -0400</date>
<date>Tue, 21 May 2001 22:37:32 -0400</date>
<date>Tue, 23 May 2001 22:37:32 -0400</date>
</root>
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