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Why is my xsl:param empty? (passed with xsl_with-param)
- To: "'xsl-list at lists dot mulberrytech dot com'" <xsl-list at lists dot mulberrytech dot com>
- Subject: [xsl] Why is my xsl:param empty? (passed with xsl_with-param)
- From: Rene de Vries <RdVries at PCL-HaGe dot nl>
- Date: Fri, 15 Jun 2001 11:04:54 +0200
- Organization: PCL HaGé b.v.
- Reply-To: xsl-list at lists dot mulberrytech dot com
I'm playing around with xsl:with-param and xsl:param, but I cant get my param passed. What do I do wrong?
I expect:
$trythis: 8
$trythis: 8
but I get
$trythis:
$trythis:
xml:
<root>
<x>bla</x>
<x>blabla</x>
</root>
xsl:
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="/">
<xsl:apply-templates>
<xsl:with-param name="trythis" select="8"/>
</xsl:apply-templates>
</xsl:template>
<xsl:template match="x">
<xsl:param name="trythis"/>
<p>
$trythis: <xsl:value-of select="$trythis"/>
</p>
</xsl:template>
</xsl:stylesheet>
Greetings Rene
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