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Re: Why is my xsl:param empty? (passed with xsl_with-param)
- To: xsl-list at lists dot mulberrytech dot com
- Subject: Re: [xsl] Why is my xsl:param empty? (passed with xsl_with-param)
- From: Conor Ryan <cryan at xmlw dot ie>
- Date: Fri, 15 Jun 2001 10:50:55 +0100
- Reply-To: xsl-list at lists dot mulberrytech dot com
just change your first template match to <xsl:template match="/root">
your param was being passed to the default template match for root and not
to x as you wanted.
hope this helps,
Conor
At 11:04 AM 6/15/01 +0200, you wrote:
>I'm playing around with xsl:with-param and xsl:param, but I cant get my
param passed. What do I do wrong?
>I expect:
>
>$trythis: 8
>$trythis: 8
>
>but I get
>
>$trythis:
>$trythis:
>
>xml:
><root>
> <x>bla</x>
> <x>blabla</x>
></root>
>
>xsl:
><xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
>
> <xsl:template match="/">
>
> <xsl:apply-templates>
> <xsl:with-param name="trythis" select="8"/>
> </xsl:apply-templates>
>
> </xsl:template>
>
> <xsl:template match="x">
>
> <xsl:param name="trythis"/>
>
> <p>
> $trythis: <xsl:value-of select="$trythis"/>
> </p>
>
> </xsl:template>
>
></xsl:stylesheet>
>
>Greetings Rene
> { @ @ }
> ^
> \__/
>
>"You don't need eyes to see, you need vision!"
>
>
>
> XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
>
>
---------
Conor Ryan,
XML Workshop Ltd,
10 Greenmount Industrial Estate, Harolds Cross, Dublin 12, IRELAND.
Email: cryan@xmlw.ie
Phone: +353 1 4547811; Fax: +353 1 4731626
Web: http://www.xmlw.ie/
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list