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XML to XML
- To: <XSL-List at lists dot mulberrytech dot com>
- Subject: [xsl] XML to XML
- From: m dot vanrootseler at chello dot nl
- Date: Fri, 22 Jun 2001 11:07:46 +0200
- Reply-To: xsl-list at lists dot mulberrytech dot com
Hi all,
I found a solution for the problem I was battling with last week in Dave's
FAQ. The XSL I found only solves part of my problem though. I want to
convert the following XML:
<line>One two. Testing.</line>
into:
<line><word>One</word> <word>two</word>. <word>Testing</word>.</line>
With the XSL below I can 'wrap' the <word> tag around words but the problem
is that any punctuation is included inside the tag as well. What I get is:
<line><word>One</word> <word>two.</word> <word>Testing.</word></line>
Has anyone any ideas how I can copy any full stops and commas but prevent
them from getting insde the <word> tags?
++++++++++
<xsl:template match="text()">
<xsl:call-template name="test"/><br/>
</xsl:template>
<xsl:template name="test">
<xsl:param name="text" select="."/>
<xsl:choose>
<xsl:when test="contains($text, ' ')">
<word><xsl:value-of select="substring-before($text, '
')"/></word>
<xsl:call-template name="test">
<xsl:with-param name="text" select="substring-after($text, '
')"/>
</xsl:call-template>
</xsl:when>
<xsl:otherwise>
<word><xsl:value-of select="$text"/></word>
</xsl:otherwise>
</xsl:choose>
</xsl:template>
+++++++++++
Problem number two. I want to add an atribute to the <word> tag which gives
the position of the word in the line: <word wordID=" ">. I've tried
<xsl:value-of select="position()"/> but this, of course, always returns '1'
due to, I guess, the recursion. Has anyone got any ideas how to get the
actual position of the word, so I get:
<line><word wordID="1">One</word> <word wordID="2">two</word>. <word
wordID="3">Testing</word>.</line>
Many thanks,
Mick
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