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RE: How do I pull out an element name out for use as aa printed variable
- To: <XSL-List at lists dot mulberrytech dot com>
- Subject: RE: [xsl] How do I pull out an element name out for use as aa printed variable
- From: "Eric Schenfeld" <ESchenfeld dot LISC_DC_PO dot LISC_DC at liscnet dot org>
- Date: Fri, 22 Jun 2001 16:41:21 -0400
- Reply-To: xsl-list at lists dot mulberrytech dot com
ok, i solved my own problem but thought that it might be nice to post how in case someone else needs it.
Recap:
-I have the following XML structure:
-<contacts>
-<contact>
- <name>xxxx</name>
- <title>Program Director</title>
- <phone>xxx.xxx.xxxx</phone>
- <email>
- <link mailto:href="mailto:xxxxxxx@xxxxxxxx.xx>xxxxxxx@xxxxxxx.xxx</link>
- </email>
-</contact>
-<contact>.....</contact>
-</contacts>
-
-The children elements of contact vary slightly between different contact lists. Because of this,
-the tables in which they appear should often have different headers (which would just be the
-name of that child element... ie name, title, phone, email ... in this case). I tried using the
-recommendation in the FAQ under the first table section but i couldn't get it to work for children
-elements instead of the attributes. Any help is appreciated.
-eric
Solution:
<xsl:for-each select="contact[1]/*">
<td>
<xsl:value-of select="name(.)"/>
</td>
</xsl:for-each>
Eric
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