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RE: count all the following nodes of a perticular parent
- To: <xsl-list at lists dot mulberrytech dot com>
- Subject: RE: [xsl] count all the following nodes of a perticular parent
- From: "Michael Kay" <mhkay at iclway dot co dot uk>
- Date: Thu, 28 Jun 2001 13:22:35 +0100
- Reply-To: xsl-list at lists dot mulberrytech dot com
> i want to count all the following nodes from the current node
> of the same
> parent
> can anybody give me a way to do this?
count(following-sibling::node())
Mike Kay
Software AG
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