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RE: count all the following nodes of a perticular parent
- To: xsl-list at lists dot mulberrytech dot com
- Subject: RE: [xsl] count all the following nodes of a perticular parent
- From: Wendell Piez <wapiez at mulberrytech dot com>
- Date: Thu, 28 Jun 2001 12:38:45 +0100
- References: <711677989624D411B81E0030050162553D96D7@ECCOLCOM01>
- Reply-To: xsl-list at lists dot mulberrytech dot com
Or
count(following-sibling::node()/descendent-or-self::node() |
following-sibling::node/descendent-or-self::node()/@*)
(depending on what you want).
Cheers,
Wendell
At 01:22 PM 6/28/01, Mike wrote:
> > i want to count all the following nodes from the current node
> > of the same
> > parent
> > can anybody give me a way to do this?
>
>count(following-sibling::node())
>
>Mike Kay
>Software AG
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Wendell Piez mailto:wapiez@mulberrytech.com
Mulberry Technologies, Inc. http://www.mulberrytech.com
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