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Count all the following nodes of a perticular parent
- To: xsl-list at lists dot mulberrytech dot com
- Subject: [xsl] Count all the following nodes of a perticular parent
- From: Jayaranga Subasinghe <jayarangas at eurocenter dot lk>
- Date: Fri, 29 Jun 2001 15:25:24 +0600
- Reply-To: xsl-list at lists dot mulberrytech dot com
hello,
thanks for the previous solutions suggested.
how can i count following nodes of a perticular node, with a perticular
parent.
the xml is something like that:
<root>
<branch>
<subBranch>
.
.
<branch>
<subBranch>
.
.
<branch_anotherType>
<subBranch>
.
<branch_anotherType>
<subBranch>
.
.
</root> .
actually i want to count how many child nodes exists after 2nd <branch>
element.
i expected to have 2 as the result
thank you.
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