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One for tomorrow :-)
- To: <xsl-list at lists dot mulberrytech dot com>
- Subject: [xsl] One for tomorrow :-)
- From: "Daniel Newman" <daniel dot newman at bis-web dot net>
- Date: Tue, 3 Jul 2001 16:48:07 +0100
- Reply-To: xsl-list at lists dot mulberrytech dot com
I've got an interesting problem, that I could fix very easily in VBscript,
but haven't got a clue (I don't think) in XSL.
My XML (I know you've all already got it :), is:
<Item id="2">
<HIN>G0200328400</HIN>
<PostCode>EC2A 1BR</PostCode>
<NameAddress1>SMITH & WILLIAMSON NOMINEES</NameAddress1>
<NameAddress2>LIMITED <CH>,</NameAddress2>
<NameAddress3>10 ACACIA AVENUE</NameAddress3>
<NameAddress4>HUTTINGDON HILL</NameAddress4>
<NameAddress5>LONDON</NameAddress5>
<NameAddress6/>
<NameAddress7/>
</Item>
And my problem is, that I want to display NameAddress1, and also need to
concat all following Nodes that end in a comma. So I need to do a:
Print NameAddress1
Set CurrentNode = NextNode()
Do While Right(CurrentNode, 1) = ","
Print CurrentNode
Set CurrentNode = NextNode()
Loop
Is something like this possible in XSL?
It's the Loop I can't find a solution to, and also how to tell the XSL to
stay on the next child.
Cheers,
Daniel.
Bis-Web Ltd.
Tel: 01993 880614
Fax: 01993 881625
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