[xsl] Re: Re: Re: RE: Re: RE: Re: XPath riddle

[Wendell Piez <wapiez at mulberrytech dot com>]

Hi Dimitre,

At 05:24 PM 7/5/01, you wrote:
>Yes, this only will not work in the more general case when the ancestor 
>element
>names to check for are generated "on the fly" from a schema.
>
>Then only the second expression I gave will work:
>
>//D/C[name(ancestor::*[contains($listOfDefiningEls, concat(' ', 
>name()))][1])='A']

Acknowledged. To be generated from the schema, the "cleaner" XPaths would 
have to be done in two passes (one to generate, one to apply them), whereas 
yours could be done in one.

>Also note, that an optimizing XPath processor will stop at the first 
>occurence of
>the above expression, while if last() is used, it will have to produce all the
>nodes.

Again, something it is often worth keeping in mind (though lists of 
ancestors usually won't be *so* long...).

Thanks,
Wendell


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Wendell Piez                            mailto:wapiez@mulberrytech.com
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