Re: [xsl] Sorting a NodeSet Contained Within a Variable

[David Carlisle <davidc at nag dot co dot uk>]

> In other words, I want to put those results into a nodeset and sort them.

As must be stated in the FAQ you can not do this in XSLT 1.0 without use
of a node-set() extension function.

Any use of xsl:variable  with content (as opposed to select attribute)
does not construct a node st but a result tree fragment. You can not
query into the structure of a result tree fragment at all, all you can
do is convert it to a string, or copy it to the result.

Most systems have an extension function ext:node-set() that allows you
to convert the result tree fragment into a node set (containing a single
node, a root node correspnding to the root pf the tree constructed by
xsl:variable)


David

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