This is the mail archive of the
xsl-list@mulberrytech.com
mailing list .
Re: Sorting a NodeSet Contained Within a Variable
- To: xsl-list at lists dot mulberrytech dot com
- Subject: Re: [xsl] Sorting a NodeSet Contained Within a Variable
- From: David Carlisle <davidc at nag dot co dot uk>
- Date: Wed, 11 Jul 2001 18:22:01 +0100
- References: <C2AC89B2CB5CD511A26B00B0D0D0F46A0EB963@EXCHANGE>
- Reply-To: xsl-list at lists dot mulberrytech dot com
> In other words, I want to put those results into a nodeset and sort them.
As must be stated in the FAQ you can not do this in XSLT 1.0 without use
of a node-set() extension function.
Any use of xsl:variable with content (as opposed to select attribute)
does not construct a node st but a result tree fragment. You can not
query into the structure of a result tree fragment at all, all you can
do is convert it to a string, or copy it to the result.
Most systems have an extension function ext:node-set() that allows you
to convert the result tree fragment into a node set (containing a single
node, a root node correspnding to the root pf the tree constructed by
xsl:variable)
David
_____________________________________________________________________
This message has been checked for all known viruses by Star Internet
delivered through the MessageLabs Virus Scanning Service. For further
information visit http://www.star.net.uk/stats.asp or alternatively call
Star Internet for details on the Virus Scanning Service.
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list