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- To: XSL-List at lists dot mulberrytech dot com
- Subject: [xsl] document()
- From: Alexey Skoblikov <leshakk at pochtamt dot ru>
- Date: Thu, 12 Jul 2001 19:02:48 +0400
- Organization: parameter
- Reply-To: xsl-list at lists dot mulberrytech dot com
Dear colleagues,
I am stuck with making appropriate code. May be you have some ready
solution. I'd be glad if you share it with me.
In processed document I have
<xgl>
<contents>
<div src="c_div1.xml">
<title level="0" text="Title 1"/>
<div src="c_div2.xml">
<title level="1" text="Title 1.1"/>
NB! <div src="c_div3.xml">
<title level="2" text="Title 1.2"/>
</div>
</div>
</div>
</contents>
</xgl>
and in c_div3.xml
<xgl> <!-- root element -->
<section ...>
<text>...</text>
NB! <style ... ptsize="16" .../>
</section>
I want to bring div[title/@text="Title 1.2"] to the higher level in
hierarchy, because @ptsize of its 1st section is 16. So I write
<xsl:template match="div[div]">
<xsl:copy-of select="div[title/@level='2' and document('{src}')//section[1]/style/@ptsize='16']"/>
</xsl:template>
<xsl:template match="div[title/@level='2' and document('{src}')//section/style/@ptsize='16']">
</xsl:template>
That makes in source document <content></content>
Where am I wrong?
Deleting the second template doesn't change the situation.
--
Best regards,
Alexey Skoblikov
Software Engineer - Adria&Co.
mailto:leshakk@pochtamt.ru
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