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sorting problem
- To: xsl-list at lists dot mulberrytech dot com
- Subject: [xsl] sorting problem
- From: DPawson at rnib dot org dot uk
- Date: Thu, 25 Oct 2001 13:27:06 +0100
- Reply-To: xsl-list at lists dot mulberrytech dot com
Given xml
<r id="d0e1588">
<bibno>050220</bibno>
<play-time>08:15</play-time>
<m100>
<surname>Tootell</surname>
<f-name>Betty</f-name>
</m100>
<m655>
<cat>Java</cat>
<term2>Indonesia</term2>
<term3>Southeast</term3>
<term4>Asia</term4>
<term5>Vehicle Failures</term5>
<term6>Accidents</term6>
<term7>Air and Space Transport</term7>
<term8>Public Safety</term8>
<term9>Social Services</term9>
<term10>Social Sciences</term10>
</m655>
<readers>Gretel Davis</readers>
</r>
lots of r elements in a <doc> wrapper.
the termX elements are 'inverse' i.e. from specific to general.
they also vary in 'depth' from 2 to 10.
I need to sort the r elements, using a revese order on m655/termX
<xsl:template match="doc">
<doc>
<xsl:apply-templates select="date"/>
<xsl:for-each select="r">
<xsl:sort select="m655/term10"/>
<xsl:sort select="m655/term9"/>
<xsl:sort select="m655/term8"/>
<xsl:sort select="m655/term7"/>
<xsl:sort select="m655/term6"/>
<xsl:sort select="m655/term5"/>
<xsl:sort select="m655/term4"/>
<xsl:sort select="m655/term3"/>
<xsl:sort select="m655/term2"/>
<xsl:sort select="m655/term1"/>
<xsl:sort select="m655/cat"/>
<!-- Copy the current node -->
<xsl:copy>
<!-- Including any attributes it has and any child nodes -->
<xsl:apply-templates select="@*|node()"/>
</xsl:copy>
</xsl:for-each>
</doc>
</xsl:template>
Sorts out the records, but by nesting.
something like
a
b
...
p
a (I.e. this is at a lower level than the previous one)
c
...
Looking for inspiration as to how I might produce a sort that
works 'across' the differing levels.
Any advice appreciated.
Regards DaveP
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